Subject: | |
From: | |
Reply To: | |
Date: | Wed, 28 Dec 2016 10:07:13 +0100 |
Content-Type: | text/plain |
Parts/Attachments: |
|
|
Hello David,
Here is how I do the calculation:
Note = FF
Sounding length = 1688 mm
Hz = 41
Constant for Yellow Brass = (Density x pi) / (9.81 x 10^12) = (8536 x pi) /
1 000 000 000 000 = 0,00000000273360192569
Kg = (Hz x Sounding length x diameter)^2 x constant for Yellow Brass =
(41 x 1688 x 1.15)^2 x 0,00000000273360192569 = 17,31584
Is something wrong in this formula?
Greetings,
Chris.
-----Oorspronkelijk bericht-----
Van: Harpsichords and Related Topics [mailto:[log in to unmask]] Namens
David Pickett
Verzonden: dinsdag 27 december 2016 16:45
Aan: [log in to unmask]
Onderwerp: Re: Yellow brass tension question
At 16:08 27-12-16, Chris Vandekerkhove wrote:
>Dear members,
>
>How much tension is there on a yellow brass string which a sounding length
>of 1688 millimeter?
>
>The other parameters are:
>
>Note = F
>Hz = 41 (derived from a1 = 415)
>Density in kg/m³ for yellow brass = 8536 >String diameter = 1,15
millimeter > >According to my calculations it should be 17,46 but I would
like a second >opinion.
>
>Sincerely,
>
>Chris.
For some reason, I make it 17.32 kg -- close enough?
::::::::::::::::::::::::::::::::::::::::::::::::::::::::::::::::::::::::
Note: opinions expressed on HPSCHD-L are those of the individual con-
tributors and not necessarily those of the list owners nor of the Uni-
versity of Iowa. For a brief summary of list commands, send mail to
[log in to unmask] saying HELP .
::::::::::::::::::::::::::::::::::::::::::::::::::::::::::::::::::::::::
::::::::::::::::::::::::::::::::::::::::::::::::::::::::::::::::::::::::
Note: opinions expressed on HPSCHD-L are those of the individual con-
tributors and not necessarily those of the list owners nor of the Uni-
versity of Iowa. For a brief summary of list commands, send mail to
[log in to unmask] saying HELP .
::::::::::::::::::::::::::::::::::::::::::::::::::::::::::::::::::::::::
|
|
|